计算(-24x³y² 8x²y³)÷(-2xy)²
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/12 04:14:21
1.25x²-y²2.-25x²+y²3.-(25x²+10xy+y²)4.5x²-24xy-5y²5.y^2n-x^2
2x/(x-8y)(x+8y)-(x+8y)/(x-8y)(x+8y)=(2x-x-8y)(x-8y)(x+8y)=(x-8y)/(x-8y)(x+8y)=1/(x+8y)
等于1/X*(X-Y)
-x^y^7+y^8)(这里有问题,x的几次方?再问:就是一次方再答:(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=(x^8-x^7y+x^
c1+c2+c32(x+y)yx+y2(x+y)x+yx2(x+y)xyr3-r2,r2-r12(x+y)yx+y0x-y0-yy-x--此时用对角线法则得=2(x+y)[x(y-x)-y^2]=-2
(x+y)(x+y)^2(-x-y)^3=-(x+y)^6
【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy
(x-y)^2*(y-x)^2*(x-y)^6=(x-y)^2*(x-y)^2*(x-y)^6=(x-y)^10再问:能详细一点吗?我,初一的再答:(x-y)^2=(y-x)^2=(x-y)^2*(x
(-x-2y)*(3x-y)=-3x^2-5xy+2y^2
【2(x-y)²-8(x-y)²(x+y)+6y(x-y)²】÷2(x-y)²=2(x-y)²÷2(x-y)²-8(x-y)²(x
(x²-y²)/x·(-x²)/(x-y)²=(x+y)(x-y)·(-x)/(x-y)²=-x(x+y)/(x-y).8y²y³
1/(x-y)-1/(x+y)-2y/(x^2+y^2)-4y^3/(x^4+y^4)-8y^7/(x^8+y^8)=【(x+y)-(x-y)】/(x-y)(x+y)-2y/(x^2+y^2)-4y^
原式=2x(2(x²-1/16y²))=4x(x+1/4y)(x-1/4y)再问:麻烦重新算一下我的题目好像出错了【抱歉再答:原式=(2x²+1/8y²)(2x
8x²y^4(-3x/4y²)/(-x²y/2)=2x²(-3x)y²/(-x²y/2)=12xy
解代数式得:-3x的平方y-2y的三次方因为1/2的平方=-1/2的平方,所以结果仍正确给分吧!嘿嘿!
将第二三行分别加到第一行,第一行都为2*(x+y),提取,得2*(x+y)*{1,1,1;y,x+y,x;x+y,x,y};再将第一行分别乘以(-y)、(-x-y)加到二三行,得2*(x+y)*{1,
解题思路:先利用完全平方公式求出x、y的值,再代入求出代数式的值。解题过程:
x2+x+y-y2
解(x-y)/(xy-y²)=(x-y)/y(x-y)=1/y