观察分式x-2 x²-6x m
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根据题意得:m+2=1,解得:m=-1,则原式=-2-1=-3.故答案是:-3.
X=-6x=-6(X/(X-2))*((X-6)/(X-3))=1-
原分式方程化为:2x+1x(x+1)=56(x+1),方程的两边同乘6x(x+1),得6(2x+1)=5x,解得x=-67.检验:把x=-67代入6x(x+1)≠0,即x=-67是原分式方程的解.则原
去分母得:2+x(x+2)=x2-4,解得:x=-3,经检验x=-3是分式方程的解.
x²+2x/x²-6x+9÷x²-4/x²-3x=x(x+2)/(x-3)^2*x(x-3)/(x+2)(x-2)=x^2/[(x-3)(x-2)]
是X/(X-2)-(1-X^2)/(X^2-5X+6)=2X/(X-3)吗?首先因式分解(X^2-5X+6)=(X-2)(X-3),显然X不等于2且X不等于3,所以等式两边同乘以(X-2)(X-3)得
当分母x-6≠0,即x≠6时,分式2x−6有意义;故答案是:x≠6.
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
1,(X×3X)/3X+1/3X=(3X^2+1)/3X2,X/2X+(6×2X)/2X=(X+12X)/2X=13/23,(X-1)/X^2-[(9×X^2)/X^2]=[X-1-(9X^2)]/X
(x-9)/(x-7)-(x+1)/(x-1)=(x-8)/(x-6)-x/(x-2)[(x-9)(x-1)-(x+1)(x-7)]/[(x-7)(x-1)]=[(x-8)(x-2)-x(x-6)]/
(X/(X-2))*((X-6)/(X-3))=1->X(X-6)=(X-2)(X-3)->X^2-6X=X^2-5X+6->X=-6
7/(x^2+x)+3/(x^2-x)=6/(x^2-1)7/x(x+1)+3/x(x-1)=6/(x-1)(x+1)分子分母同乘以x(x-1)(x+1),得7(x-1)+3(x+1)=6x10x-4
-3x³+12x²-12x=-3x(x²-4x+4)=-3x(x-2)²m²(a-2)+(2-a)=m²(a-2)-(a-2)=(a-2)(
(x-y)/(y-x)³=-1/(x-y)²(x²-9)/(6-2x)=(x+3)(x-3)/[-2(x-3)]=-(x+3)/2(x²-1)/(x-x
由题意可得x2-9=0,解得x=±3,又∵x2+3x≠0,解得x=3.
档分母=0时,无意义x^2-5x-6=0x=-1或6当分子=0,分母不等于0时,分时=0,首先要保证分式有意义x^2-3x-4x=-1或4取x=4(-1时,分式无意义)
你好,我认真解答了这道题,看最终没有实数解啊.我希望能帮到你
X-1/X-2-(X-2)/(X-3)=(X-5)/(X-6)-(X-6)/(X-7)(X-1)(X-3)-(X-2)²/(X-2)(x-3)=(X-5)(X-7)-(X-6)²/
分式计算:[(x²+2x)/(x²-6x+9)]÷[(x²-4)/(x²-3x)]原式=[x(x+2)/(x-3)²]•[x(x-3)/(