搜搜做题作业网若m^2-2mn 2n^2-8n 16=0
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(2m-n)/(n-m)+m/(m-n)+n/(n-m)=(2m-n)/(n-m)-m/(n-m)+n/(n-m)=(2m-n-m+n)/(n-m)=m/(n-m)欢迎采纳!
m+2m/n-m+n/m-n-2m/n-m=（m+2m-2m)/(n-m)+n/(m-n)=m/(n-m)+n(m-n)=-m/(m-n)+n/(m-n)=-(m-n)/(m-n)=-1
(m-n)2(n-m)7
m/(m-n)^2-n/(n-m)^2=m/(m-n)^2-n/(m-n)^2=(m-n)/(m-n)^2=1/(m-n)
2-n-1-m+m+2-m=3-m-n
一项一项通分,分母用平方差公式合并,分子进行加减,很简单就能算出来.别图省事,只要动手就能算出来的.
(m+n)^3-(n+m)(m-n)^2=(m+n)[(m+n)^2-(m-n)^2]=(m+n)[(m+n+m-n)(m+n-m+n)]=(m+n)(2m+2n)=2(m+n)^2
(m-n)^2+n(n-m)原式＝(n－m)^2+n(n-m)=(n-m)（n-m+n）=(n-m)(2n-m)因为完全平方所以(m-n)^2=(n－m)^2(a-b)(3r-t)+9(b-a)(2t
2+n(m-1)/m-m(n-2)/n
2m-n／n-m+m／m-n+n/n-m=(2m-n-m+n)/(n-m)=m/(n-m)
原式=(m²-n²-m²+2mn-n²+2mn-2n²)÷4n=(-4n²+4mn)÷4n=-4n²÷4n+4mn÷4n=-n+m
2m(m-n)平方-2n(n-m)平方=2m(m-n)^2-2n(m-n)^2=(2m-2n)(m-n)^2=2(m-n)^3
mn互为相反数,则m+n=0(8m+2n)-(7m+n)=m+n=0题目错了.修改了.
设m-n为a（a^2*a^3）^2/a^4=a^6即（m-n）^6
(m-2n)/(2m+n)=3m-2n=6m+3n5m+5n=0m=-n[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)]-{9(m-2n)/[4(2m+n)]}=[3(-n-2n)/(
﹙m－n﹚²＋2n﹙m－n﹚＝﹙m－n﹚﹙m－n＋2n﹚＝﹙m－n﹚﹙m＋n﹚.
m-n+2n^2/(m+n)=[(m-n)(m+n)+2n^2]/(m+n)=(m^2+n^2)/(m+n)
(2m-n)/(m+2n)=5∴(m+2n)/(2m-n)=1/5∴3(2m-n）/m+2n-m+2n/2m-n+3=3×(2m-n)/(m+2n)+(m+2n)/(2m-n)+3=15+1/5+3=
m(m-n)^2+n(n-m)^2=m(m-n)^2+n(m-n)^2=(m-n)^2(m+n)=(m+n)(m-n)^2
(m+n)(m-n)(m^2+n^2)=（m^2-n^2)(m^2+n^2)=m^4-n^4再问：确定？再答：平方差公式再问：没有学过