M=根下n-5 根下5-n,2m-3n=
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A=根号下M+N+3的M+N次方是M+N+3的算术平方根M+N=1/2B=根号下M+2N的M-2N+3次方是M+2N的立方根M-2N+3=1/3求M和N带回去就解就得到答案
n/m+m/n=(n²+m²)/mn(/是除号的意思)=((n+m)²-2mn)/mn因为m,n(m>n)是方程x²-2又根号下3x+2=0的两个根所以m+n=
结果是-1∵原式=0∴2m+n-1=0且m-2n-8=0∴m=2,n=-3
√(2m-3n-3)≥0,│m-2n-2│≥0∵√(2m-3n-3)+│m-2n-2│=0∴2m-3n-3=0...①m-2n-2=0.②①-2②得:n+1=0∴n=-1,m=2n+2=0∴7m-8n
既然是相反数,就是m和n两者加起来为0的,例如-1和1,-2和2就互为相反数,所以这里答案是0咯
2m+n-3=22m-n+4=3n=3m=1(N-M)^2011=2^2011
m,n>0,m^2+n^2/4=1,==>,n^2=4-4m^2>0,0
m/√n+√n>=2√(m/√n*√n)=2√mn/√m+√m>=2√(n/√m*√m)=2√n相加:m/√n+n/√m+√m+√n>=2√m+2√n所以m/√n+n/√m>=√m+√n
m-{n-2m+[3m-(6m+3n)+5n]}=m-n+2m-[3m-(6m+3n)+5n]=3m-n-3m+(6m+3n)-5n=-6n+6m+3n=6m-3n
A=m-n次根号下m+n+3是m+n+3的算术平方根,B=m-2n+3次根号下m+2n是m+2n的立方根∴m-n=2m-2n+3=3解得m=4,n=2∴A=√﹙M+N+3)=3B=2B-A的立方根=-
妹妹,你读几年级.很简单啊再问:你到底会不会写啊再答:再答:就这样好了再问:谢啦再答:你这种小题以后尽管问再问:你是学霸吗再答:没问题
(n-m)^3×(m-n)^2-(m-n)^5=-(m-n)^3*(m-n)^2-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5
|6-3m|+(n-5)²=3m-6-√[(m-3)n²](*)∵等式左侧非负∴3m-6-√[(m-3)n²]≥0∴3m-6≥√[(m-3)n²]≥0∴3m-6
根号下大于等于0n-3>=0,n>=33-n>=0,n
解原式=-(m-n)³(m-n)²-(m-n)^5=-(m-n)^5-(m-n)^5=-2(m-n)^5
S梯=(3m+4n+2m+5n)(m+2n)/2=(5m+9n)(m+2n)/2cm^2当m=2,n=3时,S梯=(5*2+9*3)(2+2*3)/2=37*8/2=148cm^2
已知m=5n,则原式=(5n/(5n+n))+(5n/(5n-n))-(n^2)/(((5n)^3)-n^2)=(5/6)+(5/4)-[1/(125n-1)]=(25/12)-[1/(125n-1)
根号下m-2n+丨2m-n-6丨=0m-2n=02m-n=64m-2n=12两式相减3m=12m=42n=m=4n=2根号下n/m×根号下m^2+n^2=√2/4x√(16+4)=√1/2x√20=√
√(2m-1)+n²-4n+4=0√(2m-1)+(n-2)²=02m-1=0n-2=0∴m=1/2n=2∴n的m次方=√2