编程输出 100-999 之间所有满足下列条件的整数:这些数既是完全平方数

#include"stdio.h"voidmain(){inti;for(i=1;i

你的程序中判断素数并加和的部分有问题在你的基础上修改如下PS:main不需要改动# include <stdio.h>int SumPrime(int&nbs

数据量小,建一个循环用暴力解决的方法#includeintmain(){intsum=0;//存入和for（inti=11;i

代码如下:运行条件:form1上有一个文本框,名称text1,一个按钮,名称command1运行结果显示在text1里面PrivateSubCommand1_Click()DimiAsIntegerM

#includevoidmain(){inti,sum=0;for(i=100;i{if(i%5==0&&i%7==0){sum+=i;}}printf("\nsum=%d

#includeintmain(void){inti,sum;sum=0;for(i=1;i

还要写吗?再问：不会啊，怎么写呢？再答：你等下，我帮你写一个再答：参考代码：#include#includeintmain(intargc,char*argv[]){\x09inti,j=0;\x09

100121144225400441484676900publicclassExercise{publicstaticvoidmain(String[]args){for(inti=100;iif(f

PrivateSubCommand1_Click()Fori=3To100Forj=2ToSqr(i)IfiModj=0ThenExitForNextIfj>Int(Sqr(i))Thens=s&i&

voidmain(){inti=0,num=0;for(i=1;i{if((i%10==3)&&(i%3!=0)){printf("%3d",i);num++;}if(num==10){num=0;p

*用vfp编写程序,输出100到200之间能被3整除不能被7整除的所有自然数.SETTALKOFFCLEARFORi=100TO200\x05IFMOD(i,3)=0.and.MOD(i,7)0\x0

voidmain(){intn=100;inta;intb;intc;for(n=100;n<=999;n++){a=n/100;b=n/10%10;c=n%10;if(n==(a*a*a+b*

C语言#includevoidmain(){inti;for(i=1;i

/楼主还是多多看看课本、#include <stdio.h>int main(){int sum = 0;int i;fo

PrivateSubCommand1_Click()Fori=100To999IfIsPrime(i)Thenn=n+1Printi;IfnMod10=0ThenPrintEndIfNextiEndS

publicclassSumOfEven{\x09publicstaticvoidmain(String[]args){\x09\x09intsum=0;\x09\x09for(inti=1;i

#includevoidmain(){inta,b,c;inti;for(i=100;i

PrivateSubCommand1_Click()Fori=100To200IfiMod30Thens=s+iPrinti;n=n+1IfnMod10=0ThenPrintEndIfNextPrin

C语言：#includevoidmain(){inti;for(i=50;i

LOCALlnI,lcZf,lnGw,lnSw,lnBwFORlnI=100to999lcZf=ALLTRIM(STR(m.lnI))lnGw=VAL(SUBSTR(m.lcZf,3,1))lnSw=