编程实现打印Fibonacci数列的前20项. 该数列的规律如下

intfunction(intn){if(n==0)return0;elseif(n==1)return1;elsereturnfunction(n-1)+function(n-2);}

publicclasstest3{publicstaticvoidmain(String[]args){Scannerscan=newScanner(System.in);System.out.pri

#includeintmain(){longa[30],i;a[0]=a[1]=0;a[2]=1;for(i=3;ia[i]=a[i-1]+a[i-2]+a[i-3];for(i=0;i{if(i!=

#includeintFibonacci(intn){if(n==0)return1;elseif(n==1)return1;elsereturnFibonacci(n-2)+Fibonacci(n-

#includevoidmain(){inta[40],i;a[0]=a[1]=1;for(i=2;i

PrivateSubForm_Click()DimnAsIntegern=Val(InputBox("请输入N:"))Dima,bAsLonga=1:b=1Fori=1TonPrinta&""&b&"

#include#include#includeusingnamespacestd;#defineM100inta[M];voidmain(){inti,j;a[0]=1;a[1]=2;i=1;

OptionExplicitDimf(40)AsLongPrivateSubCommand1_Click()DimiAsByteDimsAsLongf(1)=1f(2)=1s=2Print"No1:"

inta[101],i;a[0]=0,a[1]=1;floatt;for(i=2;i

vari,j,n:integer;beginreadln(n);fori:=1tondobeginforj:=1tondobeginif((i=1)or(i=n)or(j=1)or(j=n)or(j=

#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)

#includeintmain(){intn,i,un1,un2,un;for(n=2;n

Private Sub Form_Load()Dim I As IntegerForm1.AutoRedraw = TrueFor

#!/bin/bash#fibo.sh:Fibonaccisequence(recursive)#Author:M.Cooper#License:GPL3######----------algorit

我给你代码：#include <stdio.h>#include <stdlib.h>#define N 47int fibo

编程首先计算Fibonacci数列1,1,2,3,5,8,13,21,.的前n项（n不超过40）存入一维整型数组f中,再按%12d的格式输出每项的值,每6项换一行.说明：（1）输入数列项n,在scan

publicclassFibonacci1{publicstaticlongfib(intn){longf1=1,f2=1;longm=0;if(n

程序不能是这样的.可以是这样的ABCDEFGHIJKLMNO一般是依次得出的.不然会很麻烦那么程序可以是这样：#includemain(){charch='A',a[50];inti,n;scanf(

#includeintmain(){inti,j,k;for(i=0;i

下面的程序可以修改宏定义N的值来确定输出的数的个数#include#defineN30voidmain(){unsignedlonginta[N];inti,j;a[0]=1;a[1]=1;for(i