编程 输入两个整数 计算他们的和差积

programex1;varn,a,b,i,j,gongyueshu,gongbeishu:longint;beginreadln(a,b);if(a1和

#include<stdio.h>#define ROW 3//行数#define COL 4//列数void PlusMatrix(in

#includeintmain(){floatf1,f2;inti1,i2;printf("输入2个数\n");scanf("%f,%f",&f1,&f2);printf("f1+f2=%.2f\n"

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

用什么语言编写再问：c语言

#include"stdio.h"intmain(){inta[10][10]={0};intn,i,j,sum1=0,sum2=0;scanf("%d",&n);for(i=0;i

1：#includeintmain(){intnum,sum=0;while(scanf("%d",&num)==1&&num>0){sum+=num;\x09}printf("结果为%d",sum)

除数为0时怎样做、不为0时怎样做,不用分支结构是处理不了这种问题的,亲.再问：大哥、、、、求解。。。我郁闷了。。。再答：汗，唯一的办法就是用分支结构，if(b=0){//输出错误信息printf("除

#include"stdio.h"main(){inta=0,b=0,c=0,d=0;printf("请输入两个整数：");scanf("%d,%d",&a,&b);if(b==0)printf("输

#includevoidmain(){inta1,a2;floate;scanf("%d%d",&a1,&a2);printf("%d+%d=%d\n",a1,a2,a1+a2);printf("%d

print改成printf就可以了标准答案拿去吧除法进行的Int型的除法自己懂得#includeintmain(void){intnum1,num2;intx,y,z,k,j;printf("Ente

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

#include#includeintmain(void){intn,m,i,j,t;scanf("%d%d",&n,&m);i=m>n?m:n;j=m>n?n:m;while(j){t=i%j;i=

#includevoidmain(){inta,b,sum;scanf("%d,%d",&a,&b);sum=a+b;printf("thesumis%d",sum);}

#include#includeintmain(){inta,sum1=0,sum2=0;printf("putdata");while(scanf("%d",&a)!=0){if(a%2==0)su

dimiasinteger,nasinteger,sasinteger,kasintegerfori=1to10k=val(inputbox("请输入一个整数："))ifkmod2=1thenn=n+

第一题：programceshi1;varm,n,r,k:longint;beginreadln(m,n);k:=m*n;r:=mmodn;whiler0dobeginm:=n;n:=r;r:=mmo

额直接for(i=0;i

#include <iostream>using namespace std ;int main(){   

请问用什么语言编写?再问：我的失误！用C#