编写程序,计算s=a aa aaa aaaa aaaaa-搜答案-搜搜做题作业网

inta,n;doublesum=0;scanf("%d%d",&a,&n);for(sum=a,i=2;i

s=0k=1whilei

实际上S=n(n+1)(2n+1)/6再问：那程序怎么写啊？再答：InputnS=n(n+1)(2n+1)/6PrintS

inti,j;\x09intn,sum=0;\x09inttemp=1;\x09scanf("%d",&n);\x09for(i=1;i

#includeintmain(void){intn=0,i=0;doublep=1,q=0,s=0;printf("n=");scanf("%d",&n);for(i=1;i

VB程序PrivateSubCommand1_Click()Dima,iAsIntegeri=1Whilei<50s=s+(i+1)/ii=i+1WendPrint"s=";sEndSu

inti,S=0;for(i=1;i

#includeintmain(void){inti=1,s=0;while(i

我用php语言写的.分两个步骤,一个是计算每个节点的值,用递归算法.一个是节点的累加,用循环算法.这么好的答案,不给分,没良心.再问：谢谢了，我没说清楚，我现在学的是c++语言，真的很感谢

希望能帮到你.#include"stdio.h"intmain(){inti,j,n,s,temp;printf("请输入n的值:");scanf("%d",&n);for(i=1;i

publicclassTest{publicstaticvoidmain(String[]args){ints=0;intn=1;for(inti=0;i

#includeusingnamespacestd;voidmain(){intn,t=0;longsum=0;cin>>n;for(inti=1;i

第一种：s=0i=1dowhilei

用什么语言啊?如果是java的话就如下：ints=0；for（inti=1；i

编写程序,计算S

;MOVAX,AANDAX,B;AX=aANDbMOVBX,AXORBX,B;BX=aXORbADDAX,BXADDAX,BX;AX=2*(aXORb)+aANDbADDAX,A;AX=a+2*(aX

CLEARSETTALKOffs1=0forn=1to10s1=s1+jc(n)next"1!+2!+3!+.+10!=",s1FUNCTIONjcPARAMETERSis=1FORj=1TOis=s

#include"stdio.h"longf1(longa,longn){if(n==1)returna;elsereturn(10*f1(a,n-1)+a);}longf2(intn){longr=

main(){inta,b,c;c=a+b;scanf("%d%d",&a,&b);printf("%d",c);}

#includeintmain(){inti,s=0;for(i=1;i

#includeusingnamespacestd;intmain(){intsum=0;for(inti=1;i