编写VB程序,为一个3*3的二维数组输入任意整数,然后输出最大值及其行号和列号

dimii=0forj=100to999ifjmod3=0thenif(j-6)mod10=0theni=i+1endifendifnext没有编译运行LZ自己试试

privatesubform_click()dimnaslong,snaslongn=inputbox("请输入n")fori=0tonsn=sn+2*i+1nextmsgbox"1+3+5+...(

代码如下：PrivateSubForm_Click()DimaAsString,sAsInteger'定义变量s=1'初始化数据a=Val(InputBox("输入数值","数据输入"))'对变量赋值

放置一个command1,一个text1,不用再做其它设定,程序会自行设定各个参数,代码如下：PrivateSubCommand1_Click()DimNAsLong,IAsLong,JAsLongI

PrivateSubCommand1_Click()Dima,xAsSinglea=Val(Text1.Text)Ifa再问：x=x+a*0.2+3000*0.2怎么都乘0.2呀？

PrivateSubCommand1_Click()Dimi%Fori=100To999IfiMod7=0AndMid(CStr(i),2,1)="2"ThenPrintiNextEndSub再问：M

下面是我的代码,你也可以优化一下.PrivateSubCommand1_Click()cmdlength=Text1.TextIfLen(Text1.Text)>=3Thencmdmi=Mid(Tex

这样才完整：判断不出错.N-1省去了许多判断,提高了效率.PrivateSubCommand1_Click()DimNAsIntegerDimiAsIntegerIfIsNumeric(Text1.T

阶乘n!=n*(n-1)(n-2)(n-2)···3*2*1

PrivateSubCommand1_Click()DimsAsString,nAsInteger,iAsIntegerFori=1To100n=n+iNextiPrint"1+2+3+……+100=

DimaAsInteger'首项DimbAsInteger'末项DimcAsInteger'项数DimdAsInteger'结果PublicSubAdd()a=InputBox("首项","")b=I

*程序一*/main(){intn,i=2,isPrime=1;printf("Inputn:\n");scanf("%d",&n);while(i

PrivateSubCommand1_Click()'IntegerRandomizeLabel1.Caption=Int(Rnd*(101)-50)EndSubPrivateSubCommand2_

PrivateSubForm_Click()Dimd1AsIntegerDimd2AsSingleDimd3AsIntegerDimd4AsStringDimd5AsIntegerDimd6AsInt

dimxasinteger,dimsumasintegerforx=1to100ifxmod3=0thensum=sum+xendifnextxprintsum

将六个圆命名为“Oval1”直到“Oval6”在窗体上放6个timer控件.写入如下代码：Private Sub Form_load()'必要的初始化操作Timer1.in

拜托,这么多输入你就用列表啦,用那么多textbox,你不累我看得都累.还有,你要求的是什么尽量用数学的方式表达出来,有图更好至于你的a5d6的问题,是因为你的是字符串运算而不是数值运算,转换一下类型

'最大PublicFunctionmax(aAsInteger,bAsInteger,cAsInteger)AsIntegermax=IIf(a>b,IIf(a>c,a,c),IIf(b>c,b,c)

PrivateSubCommand1_Click()a=InputBox("请输入数值")b=InputBox("请输入数值")IfVal(a)Fori=1ToVal(a)IfVal(a)Modi=0

我HI你吧,等一下