log(a 2)化简
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![log(a 2)化简](/uploads/image/f/671934-30-4.jpg?t=log%28a+2%29%E5%8C%96%E7%AE%80)
k只需满足log(k+2)为整数即k=2^p-2根据题意,0
换底公式原式=lgb/lg(1/a)+lgb/lga=lgb/lg(a^-1)+lgb/lga=lgb/(-lga)+lgb/lga=-lgb/lga+lgb/lga=0
因为以a为底b的对数可化为同底的对数相除,即lga/lgb所以,原式=lg5/lg7+lg3/lg7+lg2/lg7=(lg5+lg3+lg2)/lg7=lg(5*3*2)/lg7=lg30/lg7=
10000是10的4次方,10是1次方,所以是4
log根号2(sin7π/8)+log根号2(sin3π/8)=log根号2(sin7π/8)(sin3π/8)=log根号2(sinπ/8)(cosπ/8)=log根号2(sinπ/4)/2=log
是不是您打错了?f(a1+a4+a6+a8)=32应该是f(a2+a4+a6+a8)=32吧?设an=a1+d(n-1)f(a2+a4+a6+a8)=2^(4a1+15d)=32f(a2)*f(a4)
对于集合B,log2(x2-5x+8)=1⇔x2-5x+8=2,解x2-5x+8=2可得x=2或3,则B={2,3},对于集合C,解x2+2x-8=0可得x=-4或2,则C={-4,2},又由A∩C=
(a2+b2)(c2+d2)=a²c²+b²c²+a²d²+b²d²再问:没化完再答:化完了,不能再化了再问:--好吧,
[log(2)(5)+log(4)(0.2)][log(5)(2)+log(25)(0.5)]=(lg5/lg2+lg0.2/2lg2)(lg2/lg5+lg0.5/2lg5)=[(lg25+lg0.
2log`5(10)+log`3(0.25)+log`1/5(125)=log5(100)+log`3(0.25)-3(中间的是以3为底的对数吗)(2)log`2(根号2)+log`9(27)+(1/
a2-b2ab-ab-b2ab-a2=a2-b2ab-b(a-b)a(b-a)=a2-b2+b2ab=ab;故选A.
原式=log2748×1242−1=log22−12−1=−12−1=−32,故答案为−32.
原式=(lg3*lg4*lg7*lg16)/(lg2*lg3*lg4*lg7)=lg16/lg2=4
log₂12-log₂3=log₂(12÷3)=log₂4=2
我没有算出来,但我肯定,一定不是1/log(60)x
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首先等比数列an中有命题:m+n=k+h则aman=akah于是a1*a10=a2*a9=a3*a8=.=a5*a6=25对数运算法则:log(ab)=log(a)+log(b)log(a)表示以m为
log(5)35+2log(1/2)√2-log(5)1/50-log(5)14=log5(35÷1/50÷14)+2log(1/2)(2^1/2)=log5(125)+2log(1/2)[(1/2)
原式=5a2-[a2+5a2-2a-2a2+6a]=5a2-[4a2+4a]=5a2-4a2-4a=a2-4a.