Java题目 给出一个整数n,其中n小于等于100000,请统计n的因数的个数.

publicvoidchageNum(intm,intn)int[]arr=newint[m];intnewarr=newint[m+n];for(inti=0;i

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

packageTest;importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersca

比如123n/100*100=100取出整百位n-100=23取出十位个位23/10=2取出10其实根本不用这么麻烦123/10=1212%10=2直接取出十位

分解质因数,日过它只有1和本身,就说明是质数～

if(a==x[i])//多了个分号

vars,n,i,t:longint;beginreadln(n);fori:=1tondobegint:=i;whilet>0dobegins:=s+tmod10;t:=tdiv10;end;end

#includeintmain(intargc,constchar*argv[]){inta;intb=0;inti=1;printf("请输入数字：");scanf("%d",&a);for(int

给你个例子看看吧privatestaticintmove=3;publicstaticvoidmain(String[]args){int[]arr={1,2,3,4,5,6,7,8,9};Integ

intcount=0;for(intm=1;.){if(m%2==1||m==1){count++;}elseif(m是十位、百位、千位...的情况,其实也是分别除10、100、1000...,再取整

publicclassTest{publicstaticvoidmain(String[]args){inta=Integer.parseInt(args[0]);intn=Integer.parse

publicstaticvoidmain(String[]args){intsum=0;chara;Scannerscanner=newScanner(System.in);intnum=scanne

varn,i,ans:integer;beginreadln(n);ans:=0;//读入,计数器置0fori:=1tondoifnmodi=0theninc(ans);//从1到n循环找到一个他的因

importjava.util.Scanner;publicclassjiechen{publicstaticvoidmain(String[]args){Scannerscanner=newScan

vari,n,r:longint;s:single;beginreadln(n);fori:=1tondobeginreadln(r);writeln(r*r*3.1415926:0:2);end;e

importjava.io.File;importjava.io.FileNotFoundException;importjava.io.FileWriter;importjava.io.IOExce

importjava.util.Scanner;publicclassMath11{publicstaticvoidmain(String[]args){Scanners=newScanner(Sys

vari,n:longint;beginreadln(n);i:=7;whilei

请问,每个人的英语课的成绩哪里来?再问：就是自己输入Scanner再答：看看符合你的要求不

varn,i,j,s:integer;x:boolean;beginread(n);s:=2;x:=true;ifn