jAVA对于一个四位数,编程计算x的每一位数字相加之和

publicclasstest3{publicstaticvoidmain(String[]args){Scannerscan=newScanner(System.in);System.out.pri

设此数为a,和为ss=0;{s+=a%10;a/=10;}循环3次即可

publicclassCat{publicstaticvoidmain(String[]args){intnum=2;drawDiamond(num);}privatestaticvoiddrawDi

/*1100x+11y=11(100x+y)=n^2,0

已通过测试,结果有两组满意请及时采纳,谢谢PrivateSubCommand1_Click()Text1=""Dimnum(8)AsIntegerFori=1To8Forj=1To8IfijThenF

inti=2123;intone,two,three,four;one=i%10;//各位two=(i/10)%10;//十位three=(i/100)%10;//百位four=(i/1000)%10

importjava.util.Scanner;publicclassHuiwen{publicstaticvoidmain(String[]args){Scannerin=newScanner(Sy

#include#includeintmain(void){intnum[5];inti=0,j=0,count=0;printf("请输入一个五位数：");for(i=0;i{scanf("%d",

C++的...我偷懒就用string写了,#include"stdafx.h"#include#include#includeusingnamespacestd;voidmain(){stringa;

publicstaticvoidmain(String[]arg){intk=0;intm=0;System.out.println("输入一个四位数");Scannerinput=newScanne

staticvoidMain(string[]args){inta=int.Parse(Console.ReadLine());intb=a%10;intc=(a/10)%10;intd=(a/100

intcount=0;for(intm=1;.){if(m%2==1||m==1){count++;}elseif(m是十位、百位、千位...的情况,其实也是分别除10、100、1000...,再取整

importjava.util.Scanner;publicclassEncpryt{publicEncpryt(){Scannerscan=newScanner(System.in);System.

package com.ectrip.swing.main;import java.util.Scanner;public class Test {\

没多少代码.如下.---------------------------------------------------------------importjava.awt.BorderLayout;

classClock{privateinthourse;privateintminute;privateintsecond;publicClock(){this.hourse=0;this.minut

#includeintis_four_digit(intvalue){return((value>=1000&&value=-9999&&value

5873÷839=1476÷738=1863÷207=2109÷703=3192÷532=1888÷472=3132÷348=1544÷193=4488÷561=5728÷716=2502÷834=2

intnum=4568;intshiwei=0,baiwei=0,qianwei=0,gewei=0;qianwei=num/1000;baiwei=(num%1000)/100;shiwei=(nu

“四位数”从0000到9999共10000个数字.其中,由三个不同数字组成的数有：C(10,3)*C(3,1)*P(4,4)/P(2,2)=10*9*8/3*2*1*3*4*3*2*1/2=4320个