F(X)=-2sin²x 2根号3sinxcosx 1
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![F(X)=-2sin²x 2根号3sinxcosx 1](/uploads/image/f/574593-33-3.jpg?t=F%28X%29%3D-2sin%C2%B2x+2%E6%A0%B9%E5%8F%B73sinxcosx+1)
1,f(x)=sin²x+√3sinxcosx+2cos²x=1-cos²x+√3/2sin2x+2cos²x=cos²x+√3/2sin2x+1=(
结果为6利用对称性可得
由题意可得:f(x)=sin(2x+π/3)-√3sin^2x+sinxcosx+√3/2=sin(2x+π/3)-√3(1/2-1/2cos2x)+1/2sin2x+√3/2=2sin(2x+π/3
利用反函数定义f//(1)=a表明f(a)=1即2sin(2a+π/3)=1sin(2a+π/3)=1/22a+π/3=2kπ+π/6或者2kπ+5π/6,k是整数即2a=2kπ-π/6或者2kπ+π
f(x)=2sinxcosx+2√3sin²x-√3=2sinxcosx+√3sin²x+√3(sin²x-1)=2sinxcosx+√3sin²x-√3cos
f(x)=2sinπ/4cosπ/4-2√3sin²π/4+√3=sinπ/2+√3(1-2sin²π/4)=1+√3cosπ/2=1
y=sinx^2+根3sinxcosx+2cosx^2=-1/2(1-2sinx^2)+1/2根3*2sinxcosx+2cosx^2-1+3/2=-1/2cos2x+二分之根3倍sin2x+cos2
f(x)=2根号3sin方x+sin2x+根号3=根号3(2sin方x+1)+sin2x=根号3(1-cos2x+1)+sin2x=2根号3-根号3cos2x+sin2x=2sin(2x-60度)+2
f(x)=2√3sin²x-sin(2x-π/3)=√3-√3cos2x-1/2sin2x+√3/2cos2x=√3-(1/2sin2x+√3/2cos2x)=√3-sin(2x+π/3)T
f(x)=sin2(x+π)+根号3sin(x+π)sin(π-x)-1\2=sin2x-根号3sin²x-1/2=sin2x+根号3/2cos2x-1=根号7/2sin(2x+γ)-1co
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|F(x1)-F(x2)|=|根号下(1+x1^2)-根号下(1+x2^2)|=|(x1^2-x2^2)/(根号下(1+x1^2)+根号下(1+x2^2))|=|(x1-x2)||(x1+x2)/(根
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f(x)=[2sin(x+π/3)+sinx]cosx-√3sin²x=[sinx+√3cosx+sinx]cosx-√3sin²x=2sinxcosx+√3cos²x-