求任意三个数的和及平均值的代码-搜答案-搜搜做题作业网

mian(){floats1=0,s2=0,x;intn1=0,n2=0,i;for(i=0;i0){s1+=x;n1++;}if(x

matlab编程：a=input('请输入第一个整数值');b=input('请输入第二个整数值');c=input('请输入第三个整数值');d=max(a,b,c)e=(a+b+c)/3其中,d是

#include#includevoidfun(intarr[],intn,int*min,int*max,float*average){inti=0,sum=arr[i];*min=arr[i];*

令这四个数分别为a,b,c,d按照题意有：1/3(a+b+c)+d=41/3(a+b+d)+c=61/3(a+d+c)+b=16/31/3(d+b+c)+a=14/3令四式相加,结果如下：1/3(3a

#include <stdio.h> int main (){ int&nbs

F2单元格输入公式=AVERAGE(IF(B2:E20,B2:E2))数组公式,按下SHIFT+CTRL+ENTER三键结束输入,再下拉复制公式或=SUM(B2:E2)/COUNTIF(B2:E2,"

#includevoidmain(){inta,b,c;intsum,max,min;doubleaverage;printf("请分别输入a,b,c三个整数的值(逗号隔开）：");scanf("%d

#include“stdio.h"voidmain(){\x09inta,b,c,sum;\x09floatave;scanf("%d%d%d",&a,&b,&c);sum=a+b+c;\x09ave

本人没学过只是编程爱好者献丑了问题1PrivateSubCommand1_Click()Text3=""DimA1AsIntegerDimA2AsIntegerDimA3AsIntegerA1=Tex

Private Sub Command1_Click()Dim i As Integer, j As Integer,&

设他们为9k5k3k(9k+3k+5k)/3=10.2k=1.8所以三个数为16.295.4

只对正数证明,令x³=a.y³=b.z³=c.x³+y³+z³-3xyz＝（x+y+z）（x²+y²+z²-x

=AVERAGE(B5,VALUE(B6),VALUE(B7),VALUE(B8))

A+B=200A+C=150B+C=160以上3项相加得2A+2B+2C=510则平均值为85

160+184+172=516516÷2÷3=86

（4+6+16/3+14/3）×1/2=10

#include#includevoidmain(){inta[10];intsum=0;intbelow_ave=0;floatave=0;inti;printf("inputteninteger:

#includevoidmain(){inti1,i2,i3,sum,avg;scanf("%d",&i1);scanf("%d",&i2);scanf("%d",&i3);sum=i1+i2+i3;

intnum1,num2,num3;floataverage;printf("pleasenum1,num2,num3:\n");scanf("%d,%d,%d",&num1,&num2,&num3)

#include"stdio.h"voidzuizhi(floatb[],intn,floatmax,floatmin,floataver);voidmain(){floata[2],max,min