c语言编写求圆的面积的格式
来源:学生作业帮助网 编辑:作业帮 时间:2024/06/23 05:29:55
#include#definePI3.1415926doublearea(doubler){returnPI*r*r;}doubleperimeter(doubler){return2*PI*r;}i
现在已经改好了,请看更改的地方:#includevoidmain(void){floata,b,h,area;/*应该声明为float*/floatget_area(float,float,float
给,已经编译运行确认:#include#include#includeintmain(){floata,b,c;floatarea,s;printf("请输入三角行的三边:");scanf("%f%f
这是辛普森积分法.给你写了fun_1(),fun_2(),请自己添加另外几个被积函数.调用方法t=fsimp(a,b,eps,fun_i);a,b--上下限,eps--迭代精度要求.#include#
#includeintmain(void){\x09\x09doublex,y=0;\x09printf("inputx");\x09scanf("%lf",&x);\x09if(x>-1)\x09{
voidmain(){floatr,s,l;floatpi=3.1415;printf("输入一个圆的半径:\n");scanf("%f",&r);if(
#include#includemain(){doublet,pi;longintn,s;t=1.0;n=1;s=1;pi=0.0;while(fabs(t)>=1e-6){pi=pi+t;n=n+2
#includeintgongyue(intm,intn){intr;if(m==n)returnm;elsewhile((r=m%n)!=0){m=n;n=r;}returnn;}voidmain(
#include"stdio.h"main(){floata[20],avg=0.00;inti;printf("Pleaseinputdatas!\n");for(i=0;i
#includeintmain(){intr;printf("请输入r:");scanf("%d",&r);printf("面积是:%f\n",2*3.1415*r*r);return0;}再问:没有
#include <stdio.h>float area(float r){ return 3.14159 *&nb
#includemain(){inta,b,c,d,n=0;scanf("%d%d%d%d",&a,&b,&c,&d);n=(a+b+c+d)/4;printf("%d\n",n);}再问:不是
#includevoidmain(){doubler,s,l;printf("请输入圆的半径\n");scanf("%lf",&r);s=3.14159*r*r;l=2*3.14159*r;print
#include//doubleellipse_area(doublea,doubleb);intmain(void){doublea,b;doubles;printf("请输入椭圆的半长轴a,半短轴
假设知道三角形的三边长为a,b,c.程序如下:#include#includedoublearea(doublea,doubleb,doublec){doublearea=0,s=0;s=(a+b+c
#include"stdio.h"#definePI3.141592653//定义πintmain(void){floatC,A,V,r;printf("请输入半径:");//提示输入scanf("%
voidjudge(inta,intb,intc)//判断三角形{if(a+b>c&&b+c>a&&a+c>b)elseif(a==b||b==c||a==c){if(a==b==c)printf("
#include#include#includeusingnamespacestd;intmain(){intr=15,h=3;doublec=2*3.14*r;doubles=pow(r,2)*3.
#includeintmain(void){inti=33;intj=5;printf("33%5==%d\n",i%j);return0;}
m=2a+2b;应该改成m=2*a+2*b;程序中2a,2b是不允许的,没有意义的.