C语言求2-N之间最大的5个质数,将其存放在数组中-搜答案-搜搜做题作业网

#include<stdio.h>intfib(inti) //用递归来实现{ if(i==1||i==2)

#includeintmain(){inti,j,sum=0;for(i=1;sum

floatmax=0;for(inti=0;i

if(flag==1&&n!=1)这里错了你少了=

#include#includeintmain(){inti=2;intn=0;ints=0;for(;s+i再问：你好。问下system("pause");这句什么意思？再答：暂停控制台。在

#include <stdio.h>#define SIZE 5int main(){ int&nbs

#include#includemain(){inti,k,t=0,n,max,min,sum=0;scanf("%d",&n);scanf("%d",&k);if(k%2==0){t++;sum+=

while(m>=1&&n

#include#includeintfib(intn){\x09inti,*A;\x09A=(int*)malloc(sizeof(int)*n);//动态申请内存\x09A[0]=1;A[1]=1

C语言求2的n次幂.

#includeintmain(){intm=0;longintresult=0;printf("enterm:");scanf("%d",&m);if(0==m){printf("2^0=0\n")

因为每次不是质数的时候你还是判断是不是c是6的倍数,这个应该放在C++后面再问：汗，我是新手菜鸟，你能帮我改正一下吗？就发改正部份就行再答：#include#includeintmain(void){

C语言求1+2+...+n=?

#includeintmain(){\x09intn;\x09unsignedinttmp=0;\x09printf("pleaseinputadata:");\x09scanf("%d",&n);\

voidmain(){inta[100],b,max,min,i,sun=0;floatping=0;printf("Pleaseenterthenumberrequiredtoenternumber

#include#includeboolisprime(intn){inti;for(i=2;i

#include"stdio.h"#include"math.h"main(){inta,b,i,j,k,t,n=0;printf("请输入两个整数:");scanf("%d%d",&a,&b);if

#includemain(){intsum=0;inti;inta;intn=0;printf("thesumis:");for(i=1000;n=a;a++)if(a>=sqr(i)){sum=su

{}yes=0;break整体是一个语句块

#includeintmain(){\x09inti,sum,n=1;\x09while(1)\x09{\x09\x09sum=0;\x09\x09for(i=1;i10000)break;\x09\

#includevoidmain(){doubles=1.0;inti,N；scanf("%d",&N);for(i=0;i

#include#includevoidmain(){intn=0;inti=0;longsum=1;scanf("%d\n",&n);for(i=1;i

C语言 求2-N之间最大的5个质数,将其存放在数组中