arrive( ) 2:00 p.m( )the open day

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arrive( ) 2:00 p.m( )the open day
Your parents will arrive (at 3 p.m)划线提问

Whenwillyourparentsarrive?希望能够帮到楼主

My student will___ home at 5 p.m.a)arrive b)reach c)arrive a

a我的学生下午5点到家.BCD都要求后面有名词作宾语,但是home表示“回家,在家”时是副词.所以只能选A.

We are going to( ) home at 5 p.m A.get to B.get C.arrive at

home在此作为副词是不能有介词的其次的话arrivehome在这里也是不能选的因为它表示的是到家了到家那个点(如果整句话为过去式表示回忆的话就要用arrivehome了表示我们5点到的家)而这里显然

He will arrive at our school at 2点 p.m 改成同义句

Hewillgettoourschoolat2o'clockintheafternoon.

已知m、n、p满足|2m|+m=0,|n|=n,p|p|=1.化简:|n|-|m-p-1|+|p+n|-|2n+1|.

俊狼猎英团队为您解答|2m|+m=0,得m=0,|n|=n,得n≥0,p|p|=1,得p=1,化简:|n|-|m-p-1|+|p+n|-|2n+1|=n-2+(1+n)-(2n+2)=n-2+2+1+

两道按要求改写句子1.We will arrive in Beijing (at 2:00 p.m).(括号部分提问)2

Whenwillyouarriveinbeijing?Therewillbenotenoughfoodforeveryonehere

They arrive ___ noonand leave ____about 7 p.m.

固定搭配:atnoon.at(时刻)

已知m,n,p都是整数,且|m-n|的三次方+(p-m)的二次方=1,则|p-m| +|m-n|+2|n-p|=

1、|m-n|=1p-m=0p=m∴|n-p|=|n-m|=1|p-m|+|m-n|+2|n-p|=0+1+2=32、|m-n|=0m=n|p-m|=1∴|n-p|=|m-p|=|p-m|=1|p-m

(m-2n+3p)(m+3n+3p)

原式=m*m+m*3n+m*3p-2n*m-2n*3n-2n*3p+3p*m+3p*3n+3p*3p=m^2+3mn+3mp-2mn-6n^2-6np+3mp+6pn+9p^2=m^2-6n^2+9p

They will arrive ___ the museum ____ 10:00a.m.A.at,at B.in,a

第一题A;第二题的A和C是一样地,就选这个答案,makeaplan

Their parents will arrive ___2.00p.m _____ the Open Day.A.at

C点钟前用介词at具体的日期前用on不明白的再问哟,请及时采纳,多谢!

已知m,n.p都是整数,且|m-n|^3+|p-m|^5=1,求|p-m|+|m-n|+2|n-p|的值

∵m、n、p都是整数,∴m-n、p-m都是整数,∴|m-n|^3、|p-m|^5都是非负整数,又|m-n|^3+|p-m|^5=1,∴|m-n|、|p-m|只能是一者为1,另一者为0.一、当m-n=1

求满足2p*p+p+8=m*m-2m的所有素数p和正整数m

PrivateSubCommand1_Click()Fori=1To2000IfPrime(Sum_Y(i))=TrueAndPrime(i)=FalseThenPrintiNextEndSub'求素

已知m,n,p都整数,且|m-n|3+|p-m|5=1,则|p-m|+|m-n|+2|n-p|=______.

m,n.p都是整数,且|m-n|3+|p-m|5=1∴|m-n|=1,p-m=0;或m-n=0,|p-m|=1①当|m-n|=1,p-m=0时p=m,|n-m|=1|p-m|+|m-n|+2|n-p|

- when will you ___ .- we will ____3 p m A.SRRIVE,ARRIVE AT

1选Aarrive是不及物动词不带宾语reach是及物动词要带宾语三点钟前要用at2.选D第一个空close近的形容词第二个空closes是动词的单三式3.选B再问:我觉得第一题选C...再答:rea

证明:m^p+n^p恒等于0(mod p),则m^p+n^p恒等于0(mod p^2),p为奇素数

由费马小定理,m^p同余m模p所以m^p+n^p同余m+n模p,即p整除m+n设n=kp-m,带入m^p+n^p二项式展开即证