搜搜做题作业网将方程6x-2=5x-2
来源：学生作业帮助网 编辑：作业帮 时间：2024/05/02 16:20:48
(x+3)/(x+2)+(x+9)/(x+8)=(x+5)/(x+4)+(x+7)/(x+6)1+(x+5)/(x+2)(x+8)=1+(x+5)/(x+4)(x+6)x=-5再问：第二步那个1是怎么
(x-6)(x^2+x+1)-x(x+1)(x-1)=x(2-5x)x^3+x^2+x-6x^2-6x-6-x^3+x=2x-5x^2-4x-6=2x6x=-6x=-1
x(2x-5)-x(x+2)=x²-62x²-5x-x²-2x=x²-6x²-7x=x²-6x²-x²+7x=67x=6
x(2x-5)-x(x＋2)=x²-62x²-5x-x²-2x=x²-6-7x=-6x=6/7如果不懂,请追问,祝学习愉快!
((X-2)(X-4)-(X-3)^2)/(X-3)(X-4)=((X-5)(X-7)-(X-6)^2)/(X-6)(X-7),-1/(X^2-7X+12)=-1/(X^2-13X+42),6X=30
4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~
9x^2+x=0把x提出来x(9x+1)=0x=0或9x+1=0所以x=0或-1/9
我给个思路吧（X+2-1/X+2)-(X+3-1/X+3)=（X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决
x分之2减去x+1分之x=1两边同乘以x（x＋1）,得2（x＋1）-x²=x（x＋1）2x²-x-2=0
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2
(2x+1)(x+2)=62x^2+4x+x+2=62x^2+5x-4
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
转化为：2X+5=06-2X=0将括号内的数看作一个整体,使原始变成A·B=0,根据乘法规则,要是A·B=0成立,存在A=0或者B=0或者A=B=0.
5x+6x-9=2x11x-2x=99x=9x=1
即x²-4=3x²-x-52x²-x-1=0
X-1/X-2-(X-2)/(X-3)=(X-5)/(X-6)-(X-6)/(X-7)(X-1)(X-3)-(X-2)²/（X-2）（x-3）=（X-5)(X-7)-(X-6)²/
解方程：(x-2)(x^2-6x-9)=x(x-5)(x-3)将方程展开：X^3-6x^2-9x-2x^2+12x+18=x^3-8x^2+15x合并同类项得：12x=18则x=18/12=3/2