1 6x-4y-1 6x﹢4y

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1 6x-4y-1 6x﹢4y
若x*x+y*y-4x+16y+13=0 ,则x=____ y=____

x*x+y*y-4x+6y+13=0(x^2-4x+4)+(y^2+6y+9)=0(x-2)^2+(y+3)^2=0x-2=0,y+3=0x=2,y=-3

x*x+4y*y+2x*x-4y+2=0求根号下5x*x+16y*y的值快啊

x*x+4y*y+2x*x-4y+2=0应该是x*x+4y*y+2x-4y+2=0可变换为(x+1)^2+(2y-1)^2=0x=-1,y=1/2,剩下的自己做一下,关键是上面一步要会

x(x-y)+4(y-x)因式分解

x(x-y)+4(y-x)=x(x-y)-4(x-y)=(x-y)(x-4)=(x-y)(X+2)(X-2)

x^2-y^2/x+y-4x(x-y)+y^2/2x-y,

(x^2-y^2)/(x+y)-(4x(x-y)+y^2)/(2x-y)=(x-y)(x+y)/(x+y)-(4x^2-4xy+y^2)/(2x-y)=(x-y)-(2x-y)^2/(2x-y)=(x

x^4-16y^4

x^4-16y^4=(x^2+4y^2)*(x^2-4y^2)=(x^2+4y^2)*(x+2y)*(x-2y)

帮因式分解谢谢,4(x+y)(x-y)^3-9(x+y)^3(x-y) 9x^2-x+1/16这两题,

4(x+y)(x-y)^3-9(x+y)^3(x-y)=(x+y)(x-y)[4(x-y)²-9(x+y)²]=(x+y)(x-y){[2(x-y)]²-[3(x+y)]

16(x-y)(x-y)-25(x+y)(x+y)=?x的4次方+4乘y的4次方=?因式分解,

16(x-y)(x-y)-25(x+y)(x+y)=[4(x-y)]²-[5(x+y)]²=(4x-4y+5x+5y)(4x-4y-5x-5y)=(9x+y)(﹣x-9y)=﹣(9

3分之2(X-Y)-4分之X+Y=-1,6(X+Y)-4(2X-Y)=16

第一个两边乘128(x-y)-3(x+y)=-128x-8y-3x-3y=-125x-11y=-12(1)第二个6x+6y-8x+4y=16-2x+10y=16x-5y=-8(2)(1)-(2)×55

5(X-3Y)-6=2X+1,3(X+Y)=4(2X-Y)+16

5(X-3Y)-6=2X+1,5x-15y-6=2x+13x-15y=7(1)3(X+Y)=4(2X-Y)+163x+3y=8x-4y+165x-7y=-16(2)(1)×5-(2)×3得15x-75

(2x-y)^2-4(x-y)(x+2y)

4x^2+y^2-4xy-4(x^2-xy+2xy-2y^2)展开化简吧!

已知集合A={(x,y)| (y-3)/ (x-1)=2,x,y∈R},B={(x,y)| 4x+ay=16,x,y∈

∵(y-3)/(x-1)=2,x≠1,可化为y-2x=1,∵A∩B=空集,∴y-2x=1方程组无解ay+4x=16∴1/a=-2/4≠1/16解得a=-2又x≠1,则y≠3,∴3a+4≠16,a≠4当

解方程组:2(x-y)/3-x+y/4=-1 ,6(x+y)-4(2x-y)=16

2(x-y)/3-x+y/4=-1(1)6(x+y)-4(2x-y)=16(2)(1)方程两边同乘以12得8(x-y)-3(x+y)=-12合并同类项得5x-11y+12=0(3)(2)合并同类项得1

因式分解 (1).(x+y)(x+y-6)+9 (2).x²-16y²-x-4y

(x+y)(x+y-6)+9=(x+y)^2-6(x+y)+9=((x+y)-3)^2=(x+y-3)^2x²-16y²-x-4y=(x+4y)(x-4y)-(x+4y)=(x+4

先化简 再求值 [(5x+3y)^2-(3y+x)(3y-x)^16]/(4x)

[(5x+3y)^2-(3y+x)(3y-x)^16]/(4x)=【25x^2+30xy+9y^2-9y^2+x^2]/4x=(26x^2+30xy)/4x=13x/2+15y/2=13/2-15/2

化简:(2x-y)²-4(x-y)(x+y)

(2x-y)²-4(x-y)(x+y)=(4x²-4xy+y²)-4(x²-y²)=4x²-4xy+y²-4x²+4y&

解方程组 10(x-y)=3(x+y)+15 6(x+y)=4(2x-y)+16

这慢慢做不就好了,这么简单的式子

(2x+y)³-(x-2y)³因式分解 -4x³y+16x²y²-16

(2x+y)³-(x-2y)³=((2x+y)-(x-2y))((2x+y)^2-(2x+y)(x-2y)-(x-2y)^2)=(2x+y-x+2y)(4x^2+4xy+y^2-2