5(3a*2b-ab*2)-4(-ab*23a*2b)
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(2-ab+2a+5b)-(3ab+2b-2a)-(3a+4b-ab)=2-ab+2a+5b-3ab-2b+2a-3a-4b+ab=a-b-4ab+2=4-4+2=2
原式=5a²b(a-b)-3ab(a-b)²-5ab²(a-b)=ab(a-b)[5a-3(a-b)-5b]=ab(a-b)(5a-3a+3b-5b)=ab(a-b)(2
3a²b-[2ab²-2(-a²b+4ab²)]-5ab²=3a²b-[2ab²+2a²b-8ab²]-5ab
(a-2b)(a^2-2ab+4b^2)-a(a-5b)(a+3b)=(a-2b)(a^2-2ab-15b^2+15b^2+4b^2)-a(a-5b)(a+3b)=(a-2b)(a^2-2ab-15b
(2a+3b-2ab)-(a+4b+ab)-(3ab-2a+2b)=2a+3b-2ab-a-4b-ab-3ab+2a-2b=3a-3b-5ab=3(a-b)-5ab=3x5-5x(-5)=40
解a²b+ab²-a³b²-a²b³=ab(a+b)-(ab)²(a+b)=-1/5×(4/5)-(-1/5)²×(4/
(3a-4ab-3b)/(a-2ab-b)=(3(a-b)-4ab)/(a-b-2ab)=(3(1/b-1/a)-4)/(1/b-1/a-2)(这一步是分子分母同时除以ab)=(3x(-5)-4)/(
5(3a^2b-ab^2)-4(-ab^2+3a^2b)=15a²b-5ab²+4ab²-12a²b=3a²b-ab²
(5a-5b-ab)-(4a-6b-3ab)=5a-5b-ab-4a+6b+3ab=a+b+2ab=3-2x2=-1
(22a+3b-2ab)-(a+4b+ab)-(3ab+2b-2a)=22a+3b-2ab-a-4b-ab-3ab-2b+2a=23a-3b-5ab题目抄差了!(22a+3b-2ab)应该是(2a+3
2(ab-3a)-3(2b-ab)=2ab-6a-6b+3ab=5ab-6(a+b)=5*(-5)-6*(-4)=-25+24=-1
化简2a-(5ab+b)+(3a-4b-ab)=2a-5ab-b+3a-4b-ab=5a-6ab-5b2(5x-1)-3(2x-4)=10x-2-6x+12=4x+10化简求值(4x+3x²
1.3a+2b-5a-b=-2a+b2.3(-ab+2a)-2(3a-ab)=-3ab+6a-6a+2ab=-a
原式=(2a-2b+3ab-3b)+(a-b+2a)-(8a-8b+ab-b)=8+9-3b+4+2a-32+3+b=-8+2a-2b=0还可以解出a和b的值带入
(2a+5b-3ab)-(a+6b-ab)-(2ab+2b-2a)=2a+5b-3ab-a-6b+ab-2ab-2b+2a=3a-3b-4ab=3(a-b)-4ab=12-12=0
-5a^2b+6ab^2-4ab-2a^2b+4ab+3=-5a^2b-2a^2b+6ab^2-4ab+4ab+3=(-5-2)a^2b+6ab^2+3=-7a^2b+6ab^2+36x+2x^2-3
(1)6x+2x-3x+x+1=6x+1其中x=5原式=30+1=31(2)1/3m-3/2n-5/6n-1/6m=1/6m-14/6n=6/1m-7/3n其中m=6,n=3原式=1-7=-6第二题一
(4/3a^2b^2-2ab)*1/2ab=2/3ab-1-2a^2*(-1/2ab+b^2)-5a*(a^2b+ab^2)=a^3b-2a^2b^2-5a^3b-5a^2b^2=-4a^3b-7a^