4xy^2-2xy 4x分解因式
来源:学生作业帮助网 编辑:作业帮 时间:2024/05/10 13:34:50
xy^2-2xy+2y-4=xy(y-2)+2(y-2)=(xy+2)(y-2)
(1-x^2)(1-y^2)+4xy=1-x²-y²+x²y²+4xy=(x²y²+2xy+1)-(x²-2xy+y²)
壹点丶dream:-2xy-x²-y²=-(2xy+x²+y²)=-(x+y)²
xy²-2xy+2y-4原式=xy(y-2)+2(y-2)=(xy+2)(y-2)
2xy+9-x^2-y^2=9-x^2-y^2+2xy=9-(x^2+y^2-2xy)=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)
解2x²y-x³-xy²=x(2xy-x²-y²)=-x(x²-2xy+y²)=-x(x-y)²
第二题用图像法画出直角坐标系x^2+y^2=25表示圆心在原点半径是5的圆2x+3y=17是一直线直线和圆的两个交点就是方程的解求两个交点的坐标直接在图上用几何解就行了
原式=xy(y-2)+2(y-2)=(y-2)(xy+2)
原式=y(x2+2x+1)=y(x+1)2,故答案为:y(x+1)2.
xy²-2xy+2y-4=xy(y-2)+2(y-2)=(y-2)(xy+2)再问:xy(y-2)+2(y-2)变更为(y-2)(xy+2)的理由是什么?再答:提取公因式(y-2)
12x^2+xy-6y^2=(4x+3y)(3x-2y)
xy(y-2)+2(y-2)=(y-2)(xy+2)
是不是x^3y+x^2y+2xy^2-4xy^3原式=xy(x^2-4y^2)+x^2y+2xy^2=xy(x+2y)(x-2y)+xy(x+2y)=xy(x+2y)(x-2y+1)
=(x²-2xy+y²)²=(x-y)的4次方
这个题目看结构,应该是出错了,好像应该是(x^2-2xy)^2+2y^2(x^2-2xy)+y^4只有这样,才能形成完全平方公式(x^2-2xy)^2+2y^2(x^2-2xy)+y^4=(x^2-2
x²+2xy+y²-1=(x+y)²-1=(x+y+1)(x+y-1)
你的式子是无法分解的,已经是最简代数式了x^2-xy+y^2=(x-y/2)^2+3y^2/4恒大于0,无法分解
9-x^2+2xy-y^2=9-(x-y)^2=[3-(x-y)][3+(x-y)]=(3-x+y)(3+x-y)
x^2-2xy+y^2-9=(x-y)^2-9=(x-y+3)(x-y-3)
x2-2xy+y2-9,=x2-2xy+y2-9,=(x2-2xy+y2)-9,=(x-y)2-32,=(x-y+3)(x-y-3).