2x分之1-x y分之1
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原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²
=(2X/3Y)*(3X/4Y)*(4/xy)=(2x*3x*4)/(3y*4y*xy)=2x/(y^3)
绝对算不出来再答:如果是一道题发图咯再问:x平方减xy加y平方分之x平方加2xy加y平方他给你条件是y分之x等于2分之1xy再问:吧xy无视掉再答:马上再答:化成Y等于2X在带入再问:然后怎么样再答:
3xy-[2xy-2(xy-2分之3xy)+xy]+3xy=6xy-[2xy-2xy+3xy+xy)=6xy-4xy=2xy=2×3×3分之1=2
(1)(xy-x²)除以xy分之x²+y²-2xy乘x²分之x-y=x(y-x)×xy/(x-y)²×(x-y)/x²=-y(2)先化简:(
1/x+1/y=-2则(x-xy+y)/(x+xy+y)分子分母同除以xy=(1/x+1/y-1)/(1/x+1/y+1)=(-2-1)/(-2+1)=3
x分之一减y分之一等于2分之1所以xy分之y-xy分之x=2分之1,xy分之(y-x)=2分之1,y-x=2分之xy,x-y=负2分之xy,所以x减y分之xy=(负2分之xy)分之xy=-xy分之(2
(x+2y-3xy)-(-2x-y+xy)=x+2y-3xy+2x+y-xy=(1+2)x+(2+1)y-(3+1)xy=3x+3y-4xy=3(x+y)-4xy=3*1/2-4*(-1/2)=3/2
原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)
1、(xy分之x²-y²)×(x-y分之x)-(y分之x);=(x+y)(x-y)/xy×x/(x-y)-x/y=(x+y)/y-x/y=(x+y-x)/y=12、6xy²
原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/
x-y分之xy=-3分之1xy分之(x-y)=-3x-y=-3xyx-2xy-y分之2x+3xy-2y=(-6xy+3xy)/(-3xy-2xy)=3/5
[4(xy-1)^2-(xy+2)(2-xy)]除以4分之1xy=[4x^2乘以y^2-8xy+4-(4-x^2y^2)]除以4分之1xy=(4x^2乘以y^2-8xy+4-4+x^2y^2)除以4分
x-x^2分之x^2-1×1-y分之xy-x=(x+1)(x-1)/x(1-x)*[x(y-1)]/(1-y)=(x+1)/(-x)*(-x)=x+1(xy-x^2)÷xy分之x-y=x(y-x)*x
由已知条件可得:x-y=-4xy,(也就是在等式两边乘xy后整理,即可),代入所求的式子里分母为-4xy+7xy,即3xy;分子为-4xy-2xy,即-6xy,化简得-2
题目不清楚..(分之1/2倍)?再问:根号下2xy分之1除以2倍根号x乘根号下xy分之2再答:^2为平方;/为分号;√为根号。1/√2xy÷2√x×2/√xy=√2xy/2xy×√x/2x×2√xy/
单项式有:3分之b²,-2,共2个.多项式有:2分之xy+3,5分之ab+x,共2个.整式有:3分之b²,2分之xy+3,-2,5分之ab+x,共4个.
是这样的形式吗?[x/(x+y)+2y/(x+y)]×[xy/(x+y)]÷(1/x+1/y)一:原式=(x+2y)/(x+y)×[xy/(x+2y)]÷[(x+y)/xy]=x²y&sup
[(xy-2)(-xy-2)-4(xy-1)^2]除以(-xy)=[-x²y²+4-4(x²y²-2xy+1)]÷(-xy)=(-x²y²+
分子上应写:(x-1)²或者x²-2x+1再问:怎么书面表达呢?能否详细一些,谢谢再答:希望你及时采纳!!!!!