2x+3y=5,2x-7y=-15解题过程
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(2x-y)(3x-2y)+(y-x)(2x-5y)=6x²-4xy-3xy+2y²+2xy-5y²-2x²+5xy=4x²-3y²
原式=(x²+4xy+4y²-3x²-2xy+y²-5y²)÷2x=(-2x²+2xy)÷2x=-x+y再问:x=-2y=二分之一再答:=5
-x^y^7+y^8)(这里有问题,x的几次方?再问:就是一次方再答:(x^8-x^7y+x^5y^3-x^4y^4+x^3y^5-xy^7+y^8)(x^2+xy+y^2)=(x^8-x^7y+x^
2(y-x)²-7(x-y)+6(x-y)-3(y-x)²=-(y-x)²-(x-y)=-(x-y)²-(x-y)=-(x-y)[(x-y)+1]=(y-x)(
2(x+2y)=x²+y²+5整理得(x-1)^2+(y-2)^2=0x=1,y=2(x²+y²)/(3x-4y)=-1
(提问者如果能清楚地说明题目会能快速得到更多人的回答,本人大致回答一下)题目原意是解三个方程组,分别是(2x+y=7,3x-4y=5),(3x+y=1,x-2y+1=0),(2x-3y=7,4x+5y
2(2x+3y)(3x+2y)-(6x-y)(2x-5y)=12x^2+26xy+12y^2-(12x^2-32xy+5y^2)=12x^2+26xy+12y^2-12x^2+32xy-5y^2=58
(x+2)(x+3)=x²+5x+6(x-4)(x+1)=x²-3x-4(y+4)(y-2)=y²+2y-8(y-5)(y-3)=y²-8y+15x²
[(x+2y)(x-2y)-(2x-y)^2+(3x-y))2x-5y)]/(-x)=(x²-4y²)-(4x²-4xy+y²)+(6x²-17xy+
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
(x-y)^5*(y-x)^3*(x-y)^2=-(x-y)^5*(x-y)^3*(x-y)^2=-(x-y)^(5+3+2)=-(x-y)^10
/>(2x-y)(3x-2y)+(y-x)(2x+5y)=6x²-3xy-4xy+2y²+5y²-2x²+5xy-2xy=6x²-2x²-7
绝对值加平方=0因为两者均大于等于0所以都是0|x+y+2|=0(2x+3y+5)²=0x+y=-22x+3y=-5x=-1y=-1有什么不明白可以继续问,随时在线等.
解(x-y)(x+y)-(x-2y)²+x(3x-5y)-(x-y)(x-2y)=(x²-y²)-(x²-4xy+4y²)+(3x²-5xy
原式=(5-8)(x-y)^2-(1+3)(x-y)=-3(x-y)^2-4(x-y)
(-3x+7y)(-7y-3x)-(x-3y)(2x+3y)=(3x-7y)(3x+7y)+(3y-x)(3y+2x)后半部分相当于(x+a)(x+b)=x^2+(a+b)x+ab=9x^2-49y^
[(x+2y)^2-(x+y)(3x-y)-5y^2]/2x=[x^2+4xy+4y^2-3x^2-2xy+y^2-5y^2]/2x=(-2x^2+2xy)/2x=y-x
(2X-3y)-(5x-y)=2x-3y-5x+y=2x-5x-3y+y=(2x-5x)+(-3y+y)=-3x-2y这样写总是全过程了吧
展开x^2-2y^2-xy=-5x^2-2y^2+xy=7所以x^2-2y^2=1xy=6上式除以下式,解分式方程x/y=3/2或-4/3(舍去)所以x^2=9y^2=4x=3y=2或x=-3y=-2