化简或计算 √20x^2y^2 z^5(x≥0,y≥0)

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/22 05:09:05
化简或计算 √20x^2y^2 z^5(x≥0,y≥0)
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z

∑是循环和例如∑a=a+b+c∑a^2=a^2+b^2+c^2∑(z-y)(x-y)/(x+y-2z)(y+z-2x)=∑(z-y)(x-y)(x+z-2y)/(x+y-2z)(y+z-2x)(x+z

1/2(x+y+z)的平方+1/2(x-y-z)(x-y+z)-z(x+y)化简为多少?

1/2(x+y+z)的平方+1/2(x-y-z)(x-y+z)-z(x+y)=½(x²+y²+z²+2xy+2xz+2yz)+½(x²-2x

运用乘法公式计算:(x+2y-3z)(x-2y+3z)

(x+2y-3z)(x-2y+3z)=[x+(2y-3z)][x-(2y-3z)]=x²-(2y-3z)²=x²-(4y²-12yz+9z²)=x&#

C++计算x=2,y=3,z=4计算z+=x++||y++||++z求x,y,z的值

/>#include<iostream>usingnamespacestd;intmain(){intx(2),y(3),z(4);z+=x++||y++||++z;cout<<

(2x+y-z)(2x-y+z)(用乘法公式计算)

=[2X+(Y-Z)][2X-(Y-Z)]=4X^2-(Y-Z)^2=4X^2-Y^2-Z^2+2YZ^2表示平方不知道对不对

化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+(z-y)(x-y)/(x-2z+y)(y+z-2x)+(x

∵x-2y+z=(x-y)-(y-z),x+y-2z=(y-z)-(z-x),y+z-2x=(z-x)-(x-y).设x-y=a,y-z=b,z-x=c,则原式=-ac/(a-b)(b-c)+(-ba

x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y)

正整数?取对数即证:2xlnx+2ylny+2zlnz>(y+z)lnx+(x+z)lny+(x+y)lnzx>y>z,lnx>lny>lnz由排序不等式得xlnx+ylny+zlnz>ylnx+zl

(2x-y+z)(2x+y-z) 用乘法公式计算

(2x-y+z)(2x+y-z)=4x^2-(y-z)^2=4x^2-y^2-z^2+2yz

若|x-2|+|Y+3|+|z-5|=O计算求|x|+|Y|+|z|的值

10再答:x=2.y=-3.z=2所以2+3+5=10再问:再答:那个给点给点财富值吗

计算球体x^2+y^2+z^2

球体体积3/4*pi*R^3三重积分用球坐标也可以,被积函数是1三重积分柱坐标被积函数是2*(根号下R^2-x^2-y^2)二重积分也可以,被积函数是2*(根号下R^2-x^2-y^2)..

乘法公式计算(x-y+z)的2次方

(x-y+z)的2次方=(x-y)²+2z(x-y)+z²=x²-2xy+y²+2xz-2yz+z²

计算(x+2y-3z)的平方+(x-2y+3z)(x+2y-3z)

(x+2y-3z)^2+(x-2y+3z)(x+2y-3z)=(x+2y-3z)[(x+2y-3z)+(x-2y+3z)]=(x+2y-3z)(2x)=2x(x+2y-3z)

计算 (1)(-3x³y/2z²)²

(-3x³y/2z²)²=(-3x³y)²/(2z²)²=9x的6次方y²/4z的4次方

(x+2y+3z)-(3x+2y-z)+(2x-3y+4z) 用直式计算

(x+2y+3z)-(3x+2y-z)+(2x-3y+4z)=x+2y+3z-3x-2y+z+2x-3y+4z=-3y+8z

化简计算 (4y+3x-5z)(3x-4y+5z)

化简计算(4y+3x-5z)(3x-4y+5z)=[3x+(4y-5z)][3x-(4y-5z)]=9x^2-(4y-5z)^2=9x^2-16y^2+40yz-25z^2

2道超难的因式分解因式分解或化简都行(y+z-2x)^2+(z+x-2y)^2+(x+y-2z)^2 因式分解a^3-a

1题设y-z=a,z-x=b,x-y=c,则a+b+c=0,y+z-2x=b-cx+z-2y=c-ax+y-2z=a-b于是原式=(y+z-2x)^2+(z+x-2y)^2+(x+y-2z)^2=(b

计算:(x-2y+z)(-x+2y+z)要过程,谢

(x-2y+z)(-x+2y+z)=〔z+(x-2y)][z-(x-2y]=z^2-(x-2y)^2=z^2-(x^2-4xy+4y^2)=z^2-x^2+4xy-4y^2

如何化简(x+y+z)(x+y-z)(x-y+z)(-x+y+z)

应用平方差公式a^2-b^2=(a+b)(a-b)(x+y+z)(x+y-z)(x-y+z)(-x+y+z)=[(x+y)^2-z^2][z^2-(x-y)^2]=-z^4+[(x+y)^2+(x-y

计算:3x-2y- [-4x+(z+3y)]

3x-2y-[-4x+(z+3y)]=3x-2y-(-4x+z+3y)=3x-2y+4x-z-3y=7x-5y-z