22÷2x=64

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22÷2x=64
先化解,在求值;(3x/x-1-x/x+1)÷x四次方-4x²/x³-x,其中x=根号2+2

原式=(3x²+3x-x²+x)/(x+1)(x-1)*x(x²-1)/x²(x²-4)=(2x²+4x)/(x+1)(x-1)*(x+1)

x-4/1x=8/3 x-0.8x=22 3/2x+2/1x=42

x-四分之一x=八分之三0.75x=八分之三x=1/2X-0.8X=220.2x=22x=22/0.2x=110三分之二X+二分之一X=427/6x=42x=42*6/7x=36

先化简再求值:(x+2/x²-2x - x-1/x²-4x+4)÷ x-4/x,其中x=3/2

(x+2/x²-2x-x-1/x²-4x+4)÷x-4/x={(x+2)(x-2)/[x(x-2)²]-x(x-1)/[x(x-2)²]}·x/(x-4)={(

(0.5+x)+x=9.8÷2

(0.5+x)+x=9.8÷22x+0.5=4.92x=4.9-0.52x=4.4x=2.2

已知(x-根号2+1)(x-2)=0,求代数式[(x-1)/(x-3)-(x-4)/x]÷(x^2+x-6)/(x^2+

注意:本题x=2时题目没意义,应该舍去(这是很多学生错误所在)这里x只能取根号2-1  

X^-1/X^+X÷(x-x/2x-1) 先化简,再计算,其中x是一元二次方程x^-2x-2=0的正数根

(x^2-1)=(x+1)*(x-1)(x^2+x)=x(x+1)通分x-(2x-1)/x=((x^2-2x+1)/x=(x-1)^2/x带回写成分式后发现约掉一个x,一个(x+1),一个(x-1)化

x+x÷3+2x-30=180

3x+x/3=180+306x+x=210*37x=630x=90

2x^2-4x/x+2`x^2+2x/x^2-4x+4÷x/3x-6,其中x=根号3/2

原式=2x(x-2)/(x+2)×x(x+2)/(x-2)²×3(x-2)/x=6x当x=√3/2时原式=3√3

(4x+2)/x+(4x-22)/(x-5)=(x-6)/(x-4)+(7x+9)/(x+1)

/>(4X+2)/X+【4(X-5)-2】/(X-5)=【(X-4)-2】/(X-4)+【7(X+1)+2】/(X+1)4+2/X+4-2/(X-5)=1-2/(X-4)+7+2/(X+1)8+2/X

152-x=(22+x)×2

152-x=(22+x)×2152-x=44+2x2x+x=152-443x=108x=108/3x=36再问:谢谢,你做的很对。再答:希望采纳,谢谢

[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013

先一个一个的展开括号项,再同项合并就行了啊[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x=[xx-xy-(xy-yy)+x(x-y)+y(x-y)]÷2x=[xx-xy-xy+yy+xx-

先化简再求值:x^3-2x^2+4x/x^2-4x+4÷x^2-2x+4/x-2,其中x=4

x^3-2x^2+4x/x^2-4x+4÷x^2-2x+4/x-2=x(x²-2x+4)/(x-2)²÷(x-2)/(x²-2x+4)=x(x²-2x+4)/(

2x+(22-x)=40

2x+22-x=40x=40-22x=18

2×(22-x)-4x=2,

2*(22-x)-4x=244-2x-4x=244-6x=244-2=6x42=6xx=7

(5x+14)÷(x+2)=?

(5x+14)÷(x+2)==(5x+14)/(x+2)最简形式,不要再算了再问:[(x+2)²+2(x+2)(x-2)-3(x+2)(x-3)]÷(x+2)=?化简再答:[(x+2)&su

方程(x+1)(x+2)(x+3)(x+4)(x+5)(x+6)(x+7)(x^2+8x+9)+64=0

1,应该是x是几次幂就有几个根吧,所以应该是7+2=9个2.-7.036622145,-6.489288572,-6.200988153,-4.734373320,-4.289168546,-2.77

11x+42-2x=100-9x-22

11x+42-2x=100-9x-2211x-2x+9x=100-22-4218x=36x=2

先化简代数式再求值(3/x+1 - x+1)÷x²-2x/x+1,其中x满足方程x/x-1+1/x=1

=[3/(x+1)-(x-1)]÷(x²-2x)/(x+1)=[3/(x+1)-(x-1)(x+1)/(x+1)]÷x(x-2)/(x+1)=[3-(x+1)(x-1)]/(x+1)÷x(x