-(-⅓x y) (六分之一x-y)
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(-1/2*xy²)³-1/6*x(xy³)²=-1/8*x³y^6-1/6*x³y^6=-7/24*x³y^6
(x+1)(y+1)
x/(xy-y²)=x/[y(x-y)]y/(x²-xy)=y/[x(x-y)]∴公分母为:xy(x-y)通分后得x/(xy-y²)=x²/[xy(x-y)]y
所谓一个多项式的次数,就是该多项式中,所有项的最高次!未知数的则需要把次数相加!比如负六分之一×x的平方×y的(m+1)次方的次数为2+m+1=m+3xy的平方的次数为43x的3次方的次数为36的次数
求数学达人来解答x²/xy-x/y=(1-x)/y3x/4x+y-x-2y/4x+y=(3x-x-2y)/(4x+y)(1-y/y+x)÷x/y²-x²=(1-y)*(y
XY(XY-X^2)(X-Y)=X^2Y(X-Y)(X-Y)=(X-Y)(X^2Y-1)再问:答案是。-X2Y.我不知道过程是如何来的。能告诉我过程吗。谢谢。负X的平方Y
对.前提是x不等于y
(x+y-2xy)(x+y-2)+(1-xy)^2=(x+y)^2-2(1+xy)(x+y)+4xy+1-2xy+x^2y^2=(x+y)^2-2(1+xy)(x+y)+(1+xy)^2=(x+y)^
xy-1+x-y=XY+X-Y-1(加法交换律)=(XY+X)-(Y+1)=X(Y+1)-(Y+1)(提取公因式X)=(Y+1)(X-1)(提取公因式Y+1)这样可以么?
=xy(x-y)×[-xy/(x-y)]=-(xy)²=-x²y²
这题少括号了吧.
x²+y-xy-x=﹙x²-xy﹚+﹙y-x﹚=x﹙x-y﹚-﹙x-y﹚=﹙x-y﹚﹙x-1﹚
【x²+xy/(x-y)】/【xy/(x-y)】=【x²(x-y)/(x-y)+xy/(x-y)】/【xy/(x-y)】={【x²(x-y)+xy】/(x-y)}/【xy
1-x-y+xy=(1-x)-(y-xy)=(1-x)-y(1-x)=(1-x)(1-y)
原式=x²y²/(x-y)^4×[-y³(x-y)³]/x³=-y^5/[x(x-y)]=-y^5/(x²-xy)
xy-x-y+1=x(y-1)-y+1=x(y-1)-(y-1)=(y-1)(x-1)
(x-1)(y-1)
Bxyy那么x为正数,因为负数a为任意有理数a^2等于0所以选B
原式=-x²y+2xy²+2x²y²-4xy³-3x³+27x³y-18x²y²+2x²y-18x&
3xy的3次方×(-½x的3次方y的4次方)除以(-六分之一x²y的3次方)²=-3/2x^4y^7÷(1/36x^4y^6)=-54y;很高兴为您解答,skyhunte