(m n) (2n-1)=11,(m-1) (4-n)=5-搜答案-搜搜做题作业网

(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)先去括号=2mn+2m+3n-3mn-2n+2m-m-4n-mn合并同类项=-2mn+3m-3n=-2mn+3(m-n)把m-n=2,

(1)已知m-n=2,mn=1所以（-2mn+2m+3n）-（3mn+2n-2m）-（m+4n+mn）=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=-6mn+3m-3n=-6mn+3(m

是6n+1-mn,100%正确.

（m+n)(m^2-mn+n^2)+(m-n)(m^2+mn+n^2)=m^3+n^3+m^3-n^3=2m^3=-2立方和公式：m^3+n^3=（m+n)(m^2-mn+n^2)立方差公式：m^3-

先合并同类项,得3(m-n)-6mn+9,代入已知数据,有结果27

-(mn-3)+3(-mn-1)-5mn=-mn+3-3mn-3-5mn=-9mn=-9*2*23=-414

(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)=-2mn+2m+3n-3mn-2n+2m-m-4n-mn=(-2mn-3mn-mn)+(2m+2m-m)+(3n-2n-4n)=-

由1/m-1/n=2得,n-m=2mn所以(3m+mn-3n)/(m-mn-n)=（mn-3*2mn)/(-mn-mn)=(-5mn)/(-2mn)=5/2

（9-2mn+2m+3n)-(m+4n+mn）=9-2mn+2m+3m-m-4n-mn=9-mn+(m-n)=9-(-1)+4=14

4(-2mn+2m+3n)-2(3m+5n-mn)=-8mn+8m+12n-6m-10n+2mn=-6mn+2m+2n=-6mn+2(m+n)=-6*(-1)+2*3=6+6=12

（4m-5n-mn)-(2m-3n+5mn)=4m-5n-mn-2m+3n-5mn=2m-2n-6mn=2(m-n)-6mn当m-n=2,mn=-1时,原式=2×2-6×（-1）=10已知A=2x^2

-MN(M^2N^5-MN^3-N)=-（-6)^3+(-6)^2-(-6)=258

-2mn+2m+3n-3mn-2n+2m-4n-m-mn=-6mn+3m-3n=-6mn+3(m-n)=6+9=15

-2(mn-3m平方)-{m平方-5(mn-m平方)+2mn},其中m=1,n=-2=-2mn+6m^2-m^2+5(mn-m^2)-2mn=-2mn+6m^2-m^2+5mn-5m^2-2mn=mn

2m的平方-3mn-n的平方-2mn-2m的平方+5mn-2n+1=-n的平方-2n+1=-1/4+1+1=7/4

2[mn+(-3m)]-3(2n-mn)=2mn-6m-6n+3mn=5mn-6m-6n=5mn-6(m+n)m+n=2mn=-3=-15-12=-27

已知mn=-1,m-n=4则(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)=-2mn+m+n-3mn-5n+5m-m-4n+3mn=-2mn+5m-8n=2+20-3n=22-3n

绝对值m-1+(n+2)²=0m-1=0m=1n+2=0n=-2-2(mn-3m²)-[m²-5(mn-m²)+2mn].=-2mn+6m²-m

m^2-mn=14mn-3n^2=-2m^2+3mn-3n^2=(m^2-mn)+3mn-3n^2+mn=1+4mn-3n^2=1-2=-1

分式m-2n/m^2-2mn=1/()

(m-2n)/(m^2-2mn)=(m-2n)/[m(m-2n)]=1/m